Deerfield is a village located in Dane County, Wisconsin. As of the 2000 census, the village had a total population of 1,971.

Geography

\nAccording to the
United States Census Bureau, the village has a total area of 3.0 km² (1.1 mi²). None of the area is covered with water.

Demographics

\nAs of the
census of 2000, there are 1,971 people, 726 households, and 527 families residing in the village. The population density is 667.6/km² (1,732.6/mi²). There are 749 housing units at an average density of 253.7 persons/km² (658.4 persons/mi²). The racial makeup of the village is 94.32% White, 1.62% African American, 0.66% Native American, 1.12% Asian, 0.00% Pacific Islander, 1.27% from other races, and 1.01% from two or more races. 2.18% of the population are Hispanic or Latino of any race. There are 726 households out of which 40.8% have children under the age of 18 living with them, 59.9% are married couples living together, 8.7% have a woman whose husband does not live with her, and 27.3% are non-families. 21.8% of all households are made up of individuals and 8.5% have someone living alone who is 65 years of age or older. The average household size is 2.71 and the average family size is 3.17. In the village the population is spread out with 30.8% under the age of 18, 7.6% from 18 to 24, 35.0% from 25 to 44, 17.5% from 45 to 64, and 9.1% who are 65 years of age or older. The median age is 32 years. For every 100 females there are 101.3 males. For every 100 females age 18 and over, there are 102.2 males. The median income for a household in the village is $50,439, and the median income for a family is $55,278. Males have a median income of $38,250 versus $27,115 for females. The per capita income for the village is $20,209. 2.4% of the population and 0.9% of families are below the poverty line. Out of the total people living in poverty, 1.8% are under the age of 18 and 6.0% are 65 or older.