Pepin is a town located in
Pepin County, Wisconsin. As of the
2000 census, the town had a total population of 580.
Geography
\nAccording to the United States Census Bureau, the town has a total area of 136.1
km² (52.6
mi²). 117.7 km² (45.4 mi²) of it is land and 18.4 km² (7.1 mi²) of it is water. The total area is 13.55% water.
Demographics
\nAs of the census of
2000, there are 580 people, 232 households, and 168 families residing in the town. The population density is 4.9/km² (12.8/mi²). There are 273 housing units at an average density of 2.3 persons/km² (6.0 persons/mi²). The racial makeup of the town is 99.14% White, 0.34%
African American, 0.34%
Native American, 0.00%
Asian, 0.00% Pacific Islander, 0.00% from other races, and 0.17% from two or more races. 0.69% of the population are
Hispanic or
Latino of any race.
There are 232 households out of which 30.6% have children under the age of 18 living with them, 63.4% are married couples living together, 5.2% have a woman whose husband does not live with her, and 27.2% are non-families. 23.3% of all households are made up of individuals and 9.1% have someone living alone who is 65 years of age or older. The average household size is 2.50 and the average family size is 2.97.
In the town the population is spread out with 25.0% under the age of 18, 6.2% from 18 to 24, 23.8% from 25 to 44, 30.3% from 45 to 64, and 14.7% who are 65 years of age or older. The median age is 42 years. For every 100 females there are 100.7 males. For every 100 females age 18 and over, there are 106.2 males.
The median income for a household in the town is $44,444, and the median income for a family is $51,053. Males have a median income of $29,722 versus $17,361 for females. The per capita income for the town is $18,902. 4.9% of the population and 4.1% of families are below the poverty line. Out of the total people living in poverty, 6.1% are under the age of 18 and 6.3% are 65 or older.
