Stockholm is a town located in
Pepin County, Wisconsin. As of the
2000 census, the town had a total population of 75.
Geography
\nAccording to the United States Census Bureau, the town has a total area of 56.3
km² (21.7
mi²). 39.8 km² (15.4 mi²) of it is land and 16.5 km² (6.4 mi²) of it is water. The total area is 29.35% water.
Demographics
\nAs of the census of
2000, there are 75 people, 35 households, and 24 families residing in the town. The population density is 1.9/km² (4.9/mi²). There are 65 housing units at an average density of 1.6 persons/km² (4.2 persons/mi²). The racial makeup of the town is 100.00% White, 0.00%
African American, 0.00%
Native American, 0.00%
Asian, 0.00% Pacific Islander, 0.00% from other races, and 0.00% from two or more races. 0.00% of the population are
Hispanic or
Latino of any race.
There are 35 households out of which 25.7% have children under the age of 18 living with them, 62.9% are married couples living together, 2.9% have a woman whose husband does not live with her, and 31.4% are non-families. 25.7% of all households are made up of individuals and 14.3% have someone living alone who is 65 years of age or older. The average household size is 2.14 and the average family size is 2.54.
In the town the population is spread out with 17.3% under the age of 18, 2.7% from 18 to 24, 18.7% from 25 to 44, 38.7% from 45 to 64, and 22.7% who are 65 years of age or older. The median age is 52 years. For every 100 females there are 87.5 males. For every 100 females age 18 and over, there are 93.8 males.
The median income for a household in the town is $32,250, and the median income for a family is $58,750. Males have a median income of $38,750 versus $19,375 for females. The per capita income for the town is $21,329. 0.0% of the population and 0.0% of families are below the poverty line.
